Equations of Motion – The Physics Hypertextbook
commonly applied in problems involving distance, velocity, and acceleration, each In considering the relationship between the derivative and the indefinite. where d is distance traveled in a certain amount of time (t), v is starting velocity, a is acceleration (must be constant), and t is time. This gives you the distance. There is a relationship between distance, velocity and acceleration. When you understand how they interact, and their equations they become.
This turns out to be the answer to a lot of questions. The symbol v is the velocity some time t after the initial velocity. Take the case of the meteor.
What velocity is represented by the symbol v? If you've been paying attention, then you should have anticipated the answer.
It could be the velocity the meteor has as it passes by the moon, as it enters the Earth's atmosphere, or as it strikes the Earth's surface. It could also be the meteorite's velocity as it sits in the bottom of a crater. Are any of these the final velocity? Someone could extract the meteorite from its hole in the ground and drive away with it.
Equations of Motion
Probably not, but it depends. There's no rule for this kind of thing. You have to parse the text of a problem for physical quantities and then assign meaning to mathematical symbols. The last part of this equation at is the change in the velocity from the initial value. Recall that a is the rate of change of velocity and that t is the time after some initial event. Rate times time is change. Move longer as in longer time.
Acceleration compounds this simple situation since velocity is now also directly proportional to time.
Try saying this in words and it sounds ridiculous. So if you only know v and d, you can't solve for a unless you also know what t is i. The answer given to this question is incorrect. The original answer apparently assumed that the velocity you knew was only the initial one.
Distance, Velocity, and Acceleration
In that case that answer is correct as stands. You seem to assume we know both the initial and final velocities.
So of course if you know two velocities you know more than if you just know one. In the formula for distance: How do you calculate for distance then?
You'll have to specify this a little more before we can answer. Is there constant acceleration until that velocity is reached, then the acceleration stops? If so, I bet you could solve it yourself. Or is there, more plausibly, one of these other situations which also lead to limiting velocities: This applies to objects whose terminal velocities correspond to small Reynold's numbers.
This applies to objects whose terminal velocities correspond to larger Reynold's numbers, including typical large falling objects. Some other effect not in the list? I think you're looking too much into my question.
Distance, Velocity, Acceleration
I don't understand what 'reynold's numbers' are. Or the time be if distance is given, but not time?
I'm also wondering if the formula gets adjusted at all to compensate for a velocity limit?